Day 15

In this lab assignment, we will examine the forced response of a circuit which performs a differentiation  that is, the circuit output is derivative with respect to time of the input to the circuit. We will apply sinusoids of various frequencies to the circuit and compare the output with our expectations based on analysis.

In the pre-lab, we calculate Vout with different frequency 1KHz, 2KHz, and 500Hz.

Calculate the percent different about Vout with different frequency.

The circuit is set up on breadboard.

This picture shows the graph when the f=1KHz. 

In the picture, we know its peak voltage is 1.1544V, but our theoretical value is 1.388V, the percent different is 16.8%.

This picture shows the graph when the f=2KHz. 

In the picture, we know its peak voltage is 2.217V, but our theoretical value is 2.776V, the percent different is 20.1%.

This picture shows the graph when the f=500Hz. 

In the picture, we know its peak voltage is 0.603V, but our theoretical value is 0.649V, the percent different is 7.1%.

From the pictures, the percent different increase with frequency. so the error may be caused by frequency increasing.